Amelia Couture Ag0114s Dress - Black/8
$128
Product data
Amelia Rose
Structured Amelia Rose product data for search, recommendations, and AI shopping agents.
What Amelia Rose can I help you find?
In the catalog
Sample Amelia Rose products
A live slice of the Amelia Rose catalog — titles, images, and prices the API returns today.
Amelia Couture 7014 Dress
$99
Amelia Couture 7057 Dress - Silver
$179
Amelia Couture 370 Dress - Dusty-mint
$160
Amelia Couture 388 Dress
$192
Amelia Couture 2050 Dress - Periwinkle/16
$169
Amelia Couture Bz030s Dress - Magenta
$85
Amelia Couture Tm1018 Dress
$189
Amelia Couture 3042 Dress - Champagne/14
$189
Amelia Couture 2136 Dress - Dark Mauve
$328
Amelia Couture 4900 Dress - Sage
$285
Amelia Couture 7085 Dress - Light Blue
$262
One endpoint
Filter Amelia Rose with a brand ID
The same search used in the demo above. Pass brand_ids to keep results inside this catalog. 1,000 free searches a month.
- Normalized titles, images, and stable brand IDs
- Live prices, availability, and merchant URLs
- Affiliate-ready offers when a rate is available
curl https://api.trychannel3.com/v1/search \
-H "x-api-key: $CHANNEL3_API_KEY" \
-H "content-type: application/json" \
-d '{
"query": "Amelia Rose products",
"filters": {
"brand_ids": [
"qVxs"
]
},
"limit": 20
}'from channel3_sdk import Channel3
client = Channel3()
response = client.products.search(
query="Amelia Rose products",
filters={"brand_ids": ["qVxs"]},
limit=20,
)import { Channel3 } from "@channel3/sdk";
const client = new Channel3();
const response = await client.products.search({
query: "Amelia Rose products",
filters: {
brand_ids: ["qVxs"],
},
limit: 20,
});Categories
Broader product-data APIs for the same shopping workflows.
More brands
Other large catalogs available through the same API.
FAQs
How developers pull Amelia Rose into agents, search, and affiliate flows.
For Amelia Rose
Do you work at Amelia Rose?
Channel3 can help Amelia Rose show up more accurately across AI shopping apps. No technical work. Most teams are live the same week.